Question on Time Dilation Experiment

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SUMMARY

The forum discussion centers on the 1971 time dilation experiment involving atomic clocks, one on a plane and the other at a US naval observatory. The experiment demonstrated that the clock on the plane recorded a smaller time by approximately 3 E -7 seconds, consistent with the predictions of special relativity. A user questions the assumption that the plane is the moving frame and the observatory is stationary, proposing an alternative perspective where the Earth is the moving frame. The discussion clarifies that both gravitational time dilation and the relative motion of the Earth were accounted for in the experiment, reinforcing the validity of the results.

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  • Understanding of special relativity principles
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  • Knowledge of atomic clock technology
  • Basic grasp of inertial frames of reference
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shinta
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I understand the idea that, given two frames of reference, and measuring for a time T defined as the time between two events, T measured in the moving frame will be less than T measured in the stationary frame by a factor of (1-v/c)^1/2.

So, they did this experiment in 1971 where they had two atomic clocks-- one on a plane that was sent around the world, and one at a US naval observatory. After its round trip, the clock on the plane showed a smaller reading by about 3 E -7, which agrees with the predicted time dilation (within error).

My questions is, why do we assume the plane is the moving frame, and the naval observatory the stationary frame? What if, instead of seeing the plane as moving, imagine the following:

1. The plane is suspended above the naval observatory.
2. An observer in space is watching the Earth spin around its axis.
3. At some point the observer grabs hold of the plane so that the Earth continues to spin "underneath" the plane while the plane itself is held "in place" wrt the observer.
4. After 24 hours, the plane will be back in the position where it was before.

In this case, can't we argue that the Earth is the moving frame, and thus the atomic clock on the naval observatory should have the smaller reading? And, couldn't this essentially involve the same mechanics as the 1971 experiment, which resulted with the plane's atomic clock with the smaller time? It seems to me that which frame is chosen as the moving frame is arbitrary, so the idea that the "moving" frame's measured time should be less than the "stationary" frame's time doesn't seem right, since "moving" and "stationary" classifications are arbitrary. Or aren't they?
 
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shinta said:
I understand the idea that, given two frames of reference, and measuring for a time T defined as the time between two events, T measured in the moving frame will be less than T measured in the stationary frame by a factor of (1-v/c)^1/2.

So, they did this experiment in 1971 where they had two atomic clocks-- one on a plane that was sent around the world, and one at a US naval observatory. After its round trip, the clock on the plane showed a smaller reading by about 3 E -7, which agrees with the predicted time dilation (within error).

My questions is, why do we assume the plane is the moving frame, and the naval observatory the stationary frame? What if, instead of seeing the plane as moving, imagine the following:

1. The plane is suspended above the naval observatory.
2. An observer in space is watching the Earth spin around its axis.
3. At some point the observer grabs hold of the plane so that the Earth continues to spin "underneath" the plane while the plane itself is held "in place" wrt the observer.
4. After 24 hours, the plane will be back in the position where it was before.

In this case, can't we argue that the Earth is the moving frame, and thus the atomic clock on the naval observatory should have the smaller reading? And, couldn't this essentially involve the same mechanics as the 1971 experiment, which resulted with the plane's atomic clock with the smaller time? It seems to me that which frame is chosen as the moving frame is arbitrary, so the idea that the "moving" frame's measured time should be less than the "stationary" frame's time doesn't seem right, since "moving" and "stationary" classifications are arbitrary. Or aren't they?
You are correct, in this case the clock on the surface of the Earth is not stationary since an observer in an inertial frame (e.g. ECI frame) would see the surface observer go around once per 24 hours. That was taken into account, as was the gravitational time dilation by the fact that the airplane clocks were at a higher elevation. Also, they sent some clocks east and some west with the eastbound clocks losing 59 ns and the westbound clock gaining 273 ns, in accordance with the general relativity predictions. This, and other relevant tests, are summarized in the http://www.edu-observatory.org/physics-faq/Relativity/SR/experiments.html#Twin_paradox".
 
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Thank you! That clears up a lot. The book I was reading didn't mention they sent out two planes, it just mentioned they sent out one plane, and I see now they only mentioned the Eastward plane. I couldn't get over my confusion with the one plane story; the two plane story makes a lot more sense. Also, I realized that I had a typo: v/c should've been (v/c)^2.

BTW, I was reading this in an Appendix of Eisberg and Resnick's Quantum Physics. I guess they assume students have already covered special relativity, but it's been a few years for me, and even if this stuff is in their appendix, it would've been nice if they elaborated on points such as this one.
 

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