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Question on triple integral polar

  1. Apr 9, 2009 #1
    Find the mass of a solid bounded by
    x = (4-y2)1/2
    y = 0
    z = 0
    z = 1 + x
    with density = y

    i understand how to set it upand transform to polar and how to do it but my teacher said its supposed to be -pi/2 to pi/2 for the integral with respect to theta. shouldnt it be 0 to pi/2 because its bounded by y = 0?
     
  2. jcsd
  3. Apr 9, 2009 #2
    Maybe "y=0" should be "x=0"? The given equations don't seem to make sense without x=0 being included.
     
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