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JD_PM

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## Homework Statement

$$\int_{-23/4}^4\int_0^{4-y}\int_0^{\sqrt{4y+23}} f(x,y,z) dxdzdy$$

Change the order of the integral to

$$\iiint f(x,y,z) \, \mathrm{dydzdx}$$What I have done

It is just about:

From ##x=0## to ##x=\sqrt{4y+23}##

From ##z=0## to ##z=4-y##

From ##y=\frac{x^2-23}{4}## to ##y=4##

So

$$\int_0^{\sqrt{23}}\int_0^4\int_{\frac{x^2-23}{4}}^{4} f(x,y,z) dydzdx$$

But this is incorrect. What am I missing?

Thanks

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