High School Question regarding using the expression $dE_{int}$=nC_vdT$

Click For Summary
SUMMARY

The discussion clarifies the application of the equation $dE_{int} = nC_v dT$ in the context of the first law of thermodynamics, specifically during adiabatic processes where heat transfer (Q) is zero. It establishes that for an ideal gas, the change in internal energy (dE) is directly related to the work done (dW) through the specific heat capacity at constant volume (C_v). The equation $dE = -dW$ is confirmed as valid under these conditions, emphasizing that internal energy is a function of temperature alone for ideal gases.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Familiarity with adiabatic processes
  • Knowledge of specific heat capacity (C_v) and its implications
  • Basic principles of ideal gas behavior
NEXT STEPS
  • Study the derivation of the first law of thermodynamics in detail
  • Explore the concept of adiabatic processes in thermodynamics
  • Learn about the relationship between internal energy and temperature for ideal gases
  • Investigate the implications of specific heat capacities in various thermodynamic processes
USEFUL FOR

Students of thermodynamics, physicists, and engineers seeking to deepen their understanding of energy transfer in adiabatic processes and the behavior of ideal gases.

Harikesh_33
Messages
24
Reaction score
4
The first law of Thermodynamics states that the change in Internal energy is equal to the sum of Heat gained or lost by the system and work done by the system or on the system .

$dE=Q-W$...(1).

In an Adiabatic process ,Q=0 .

Therefore $dE=-W$ .

Now (https://phys.libretexts.org/Bookshelves/University_Physics/Book:_University_Physics_(OpenStax)/Book:_University_Physics_II_-_Thermodynamics_Electricity_and_Magnetism_(OpenStax)/03:_The_First_Law_of_Thermodynamics/3.07:_Adiabatic_Processes_for_an_Ideal_Gas)

here specific heat capacity at Constant volume is used instead of internal energy (ie) $dE=nC_vdT$ .

How can this specific heat be used here isn't the Volume changing (through Work done ?) .

How can $nC_vdT$=-dW$ be used ?
 
Science news on Phys.org
@Harikesh_33, it's worth noting that to make Latex render correctly here, you enclose the code between a pair of double hash-signs (##\text {##Your Latex code here##}##).

For example, doing this for nC_vT=-dW gives ##nC_vT=-dW##.

Or you can similarly use a pair of double dollar-signs to render the code on its own line. For example $$nC_vT=-dW$$Use the preview-toggle (top right on edit-toolbar) to check before posting.
 
In thermodynamics, the correct equation to use for ##C_v## is in terms of the internal energy E rather than heat Q: $$C_v=\frac{1}{n}\left(\frac{\partial E}{\partial T}\right)_V$$In the case of an ideal gas, E is a function only of T, and not V. So, for an ideal gas, we can write that $$dE=nC_vdT\tag{ideal gas}$$So, for an adiabatic reversible process of an ideal gas, we have $$dE=nC_vdT=-dW$$It's as simple as that.
 
  • Like
Likes Lord Jestocost and vanhees71

Similar threads

  • · Replies 22 ·
Replies
22
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
27K
  • · Replies 1 ·
Replies
1
Views
2K