Question regarding water physics /

  • Thread starter Thread starter wittyusername
  • Start date Start date
  • Tags Tags
    Physics Water
AI Thread Summary
The discussion revolves around the physics of an automatic water feeder and how it maintains water levels. It highlights that the pressure differential between the atmospheric pressure outside the bottle and the lower pressure inside creates an upward force that prevents the complete discharge of water. When the water level in the bowl drops, air enters the bottle, allowing water to flow out until the bowl refills sufficiently. This process relies on the balance of pressure and the creation of a partial vacuum in the bottle. Understanding these principles clarifies the mechanics behind the operation of such feeders.
wittyusername
Messages
2
Reaction score
0
This will probably be obvious to most of you so my apologies in advance. Some classmates and I got into a discussion about how an automatic feeder like this (http://i.ebayimg.com/t/Auto-Refill-...QCGk~$(KGrHqEH-C0EtrFJ6qq-BLdHF((cVg~~_35.JPG ) would work. When thinking about it I had guessed that it may be similar to hydraulics where the high pressure of the column would be countered by a large surface area in the pool (where a classmate had suggested atm pressure would be part of the opposing force here).

Other classmates suggested that when the water level is low enough air can displace water (essentially creating a vacuum in the bottle). Can anyone shed light on the actual physics at play here?

Your time is much appreciated.
 
Last edited:
Physics news on Phys.org
I can't see the photo, but assume that the column is sealed. The weight of the water would result in the water moving downwards somewhat until the pressure differential of 1 atm outside at the surface of the water and the lower than ambient pressure at the top of the column results in an equal and opposing upwards force on the water, preventing further flow.
 
!BlzpPLQCGk~$(KGrHqEH-C0EtrFJ6qq-BLdHF((cVg~~_35.JPG


sorry about that, hopefully that works better

maybe I didn't understand the response (and you answered it) but I'm still unsure what is preventing the entire discharge of the bottle. Is it merely pressure such as in a hydraulics equation (F1A2 = F2A1) or is it a vacuum created in the bottle?
 
wittyusername said:
Maybe I didn't understand the response (and you answered it) but I'm still unsure what is preventing the entire discharge of the bottle. Is it merely pressure such as in a hydraulics equation (F1A2 = F2A1) or is it a vacuum created in the bottle?
The vacuum created in the bottle is the source of the pressure difference, since the outside pressure remains at 1 atm. When the water level in the bowl drops below the opening in the bottle, then water will fall out and air will be drawn into the bottle, until the water level in the bowl rises above the opening in the bottle, preventing air from flowing inwards, and then the water moves down slightly resulting in a partial vacuum in the bottle.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...

Similar threads

Replies
4
Views
3K
Replies
11
Views
7K
Replies
10
Views
3K
Replies
8
Views
5K
Replies
2
Views
3K
Replies
4
Views
3K
Back
Top