Question: What force will a 30 kg meteor experience at the same altitude?

[MiniOreo1998]

Homework Statement

A 12 kg meteor experiences an acceleration of 7.2 m/s², when falling towards the Earth.

A) How high above the Earths’ surface is the meteor?

B) What force will a 30 kg meteor experience at the same altitude?

Starting to get more comfortable with my calculations. If there are any blunders or things I could have done to make my work more clear, any suggestions would be appreciated.

Homework Equations

r = √ G m / g

The Attempt at a Solution

A)

r = √ G m / g

r = (6.67 x 10^-11) (5.98 x 10²⁴) / 7.2 = 7.4 x 10⁶

7.4 x 10⁶ - 6.38 x 10⁶ = 1060

r = 1060 km

B)

Mass is irrelevant

 

[Simon Bridge]

Well done - I had a slight hesitation there thinking it may be a terminal velocity problem but the distance is too great for that and the context all wrong.

A. finesse the long-answers by writing a sentence stating the result:
"the meteor is 1060km above the Earth's surface".

B. Mass is relevant - the acceleration of gravity does not depend on the mass but the question asks for force.

 

[haruspex]

r = 1060 km

Right answer, but I would have calculated it using ratio to 9.8m/s²: $(R+x)^2g_{R+x}=R^2g_R$

Mass is irrelevant

Read the question more carefully.

 

[MiniOreo1998]

Well done - I had a slight hesitation there thinking it may be a terminal velocity problem but the distance is too great for that and the context all wrong.

A. finesse the long-answers by writing a sentence stating the result:
"the meteor is 1060km above the Earth's surface".

B. Mass is relevant - the acceleration of gravity does not depend on the mass but the question asks for force.

Right answer, but I would have calculated it using ratio to 9.8m/s²: $(R+x)^2g_{R+x}=R^2g_R$

Read the question more carefully.

Wow, completely misread the question. How embarrassing..

Then F = m a,
F = (30) (7.2)
F = 216 N [toward Earth]