QuestionExploring the Hubble Constant: Calculating Distance and Limitations

[_Mayday_]

The Question

One possible value for the Hubble constant is 65Kms Mpc. Calculate in Mpc, the distance from Earth for agalaxy trallening at the speed of light, 3.0\times10^{8}

Attempt

v=Hd

v=3\times10^8

H= 65Km s Mpc

First I will convert the constant to ms so that I have both in S.I. units.

v=3\times10^8 ms

H= 6.5 \times10^4 ms Mpc

Now I will just plug these values in!

\frac{3\times10^8}{6.5 \times10^4} = 4.6\times10^4 Mpc

Question
State what this distance represents.

Answer

This is the distance the galaxy is away from earth?

_Mayday_

 

[_Mayday_]

Sorry, is this poorly set out? Is there something I have not included?

 

[apelling]

You've made a slip in the final calculation (3x10^8)/(6.4x10^4) is not 4.6x10^4, that aside your method is correct.

The significance of your answer is more than just the distance to a galaxy in this case because the recession velocity is the speed of light.

Could the recession velocity be higher than this?
Could we see any galaxies beyond this one?