Quick Calculus Help: $\nabla$ of $(r^-2) \hat{r} \times \hat{z}$

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SUMMARY

The discussion focuses on calculating the curl of the vector field \((r^{-2}) \hat{r} \times \hat{z}\) using the appropriate coordinate system. The user initially attempted to apply the curl formula in spherical coordinates, which led to confusion and an incorrect result of zero. The correct approach involves using cylindrical coordinates, as the variable \(z\) does not belong to the spherical coordinate system. The correct application of the curl formula \(\nabla(A \times B) = B(\nabla \times A) - A(\nabla \times B)\) is essential for accurate results.

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Homework Statement



\nabla of (r^-2)rhat x zhat

Homework Equations



\nabla(AxB) = B(\nablaxA) - A(\nablaxB)


Using cylindrical coordinates and curl in cylindrical with the above equation, I get zero?
But I think I am wrong?
Any help?
 
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I didn't get zero. Let's see what you did, then we can tell you where you're going wrong.
 
I am using the formula for curl in spherical, I konw I said cylindrical.
Taking the first cross product, zhat(\nabla x r^2 rhat) I use the ffact its in the rhat direction, so in the curl formula, sub r^2 for all r direction components. However they are then partially differentiated and I get zero, as the r^2 has no phi or theta components does it?
 
sm1t said:
I am using the formula for curl in spherical, I konw I said cylindrical.

You should be using cylindrical. "z" isn't a spherical coordinate.
 

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