1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Quick clarification/question on Electric Field at a point

  1. Feb 28, 2017 #1
    1. The problem statement, all variables and given/known data
    http://i.imgur.com/wBdUomo.png
    wBdUomo.png
    Another simpler way to ask the question is if the electrical potential at a point is zero, is the electric field at that point also zero?

    2. Relevant equations
    v = kq/r
    E=kq/r^2
    F=qe

    3. The attempt at a solution

    http://i.imgur.com/wBdUomo.png

    Alright, so I've done the part a) in the following manner.


    http://i.imgur.com/jB9oOP0.png
    jB9oOP0.png
    Now, this is the first step in part b)

    http://i.imgur.com/BOKG70A.png
    BOKG70A.png
    We solved for cos theta by using adjacent/hypotenuse from the triangle we made earlier.
    Now, assume the question said that the distance is way more smaller than x. d <<<<<x.

    For the first question, that would make it so everything is over 50 which makes electric potential at point P zero. However, in part b what would we replace cos theta with? I was thinking of doing 0/50 (since d is virtually zero) and then the E1 is equal to zero. I'm not sure if that is what should be done
     
    Last edited by a moderator: Feb 28, 2017
  2. jcsd
  3. Feb 28, 2017 #2
    Your pictures are very hard to read. Please take the trouble to type out your working. It is disrespectful to forum members to expect them to make the effort to read your scrawl if you can't make the effort to type it legibly. Please read the guidelines: https://www.physicsforums.com/threads/guidelines-for-students-and-helpers.686781/
    I think part a is right, and I think part b is a factor of 1000 out, though I can't tell what you've done. Please show your full working if you want any more help.
     
  4. Feb 28, 2017 #3
    All I need is in regards to part b. I'm sorry if I was disrespectful I just don't know how to go about writing it. This is the scenario I'm stuck with.

    So i'm given a horizontal distance d which is d = 1cm. And I get a vertical distance which is x = 50 cm. Now we we can create a right traingle. Now if we did adjacent/hypotenuse. (Half of the d over x) We'd get 0.5/50.

    However, let's assume all that's given is that d is much smaller than x. d <<<< x.

    Would I write 0/50 which is then 0? This part multiplies with an equation so if I did it this way the entire equation would be zero.
     
  5. Feb 28, 2017 #4

    kuruman

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    The way to handle this is to find an algebraic expression for what you need first. Add any fractions that need adding. Then factor terms containing x so that you get the ratio x/d instead of just x and d separately. For example ##x + d = x(1 +d/x)## Cancel any terms that appear in the numerator and denominator. Then set ##d/x=0## and see what is left.

    On edit: If that doesn't work, you will have to use a Taylor expansion for small d/x and keep the leading term.
     
    Last edited: Feb 28, 2017
  6. Feb 28, 2017 #5

    gneill

    User Avatar

    Staff: Mentor

    You can type equations using normal text making using of the x2 and x2 buttons in the edit panel top bar to produce subscripts and superscripts, the special characters including the Greek alphabet and many handy math symbols via a menu accesses via the ##\Sigma## button also in the top bar, or by using LaTeX syntax. See: LaTeX
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Quick clarification/question on Electric Field at a point
Loading...