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Quick complex analysis (integration) question

  1. Mar 7, 2008 #1
    I want to show that the integral from -1 to 1 of z^i = (1-i)(1+exp(-pi)/2

    where the path of integration is any contour from z=-1 to z=1 that lies above the real axis (except for its endpoints).

    So, I know that z^i=exp(i log(z)) and the problem states that |z|>0, and arg(z) is between -pi/2 and 3pi/2. But we didn't study how to integrate z^(complex number) in class, and I"m really confused on how to do this.

    So, how do I integrate this?
  2. jcsd
  3. Mar 7, 2008 #2


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    You could pick a sample contour like z=exp(it) for t=0 to pi. Then log(z)=it, dz=i*exp(it)*dt. Change it into a t integration. You could also just use the antiderivative of z^i=z^(i+1)/(i+1) since you aren't passing over any branch cuts.
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