Need Help Factoring x^3 + 8? Quick and Easy Solutions Available!

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To factor the expression x^3 + 8, recognize it as a sum of cubes, which can be expressed as (x + 2)(x^2 - 2x + 4). The formula used is a^3 + b^3 = (a + b)(a^2 - ab + b^2), with a = x and b = 2. To find factors, apply the Remainder and Factor Theorems by testing values like f(1), f(-1), and f(2) to identify roots. In this case, f(-2) = 0 indicates that x + 2 is a factor, and synthetic or long division can be used to determine the remaining factor.
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Can someone help me factor x^3 + 8? I totally forgot how to do that :S
 
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We must note that this is an expression of the form a^3+b^3=(a+b)(a^2-ab+b^2), where in this case a=x and b=2.
 
Usually to factor things ,use the remainder and Factor theorem.

Let f(x)=x^3 + 8
try f(1,-1,2,etc) and when you get x=a such that f(a)=0. x-a is a factor of f(x)

For your example; f(-2)=0 so that x+2 is factor of f(x)...you can use synthetic division or long division to get the other factor.
 
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