Quick Fermi Energy QuestionFree electrons?

Click For Summary
SUMMARY

The discussion centers on the derivation of the Fermi energy expression for a solid, specifically the formula Ef = h^2/2m . (3.pi^2.N/V)^2/3. It clarifies that the term N/V refers to the density of free electrons, as the Fermi energy pertains to the highest occupied energy level at absolute zero, which includes only free valence electrons and not bound electrons. The distinction is made that bound electrons do not contribute to metallic properties, aligning with the principles of the Landau Fermi Liquid theory, which models valence electrons as a gas of quasi-particles that behave similarly to free electrons.

PREREQUISITES
  • Understanding of Fermi energy and its significance in solid-state physics
  • Familiarity with the concept of free electron gas models
  • Knowledge of Landau Fermi Liquid theory
  • Basic principles of quantum mechanics related to electron behavior
NEXT STEPS
  • Research the derivation of Fermi energy in solid-state physics
  • Study the implications of the free electron gas model in metals
  • Explore the Landau Fermi Liquid theory in detail
  • Examine the role of bound electrons in metallic properties
USEFUL FOR

Physicists, materials scientists, and students studying solid-state physics or quantum mechanics, particularly those interested in the behavior of electrons in metals and their contribution to material properties.

Master J
Messages
219
Reaction score
0
Quick Fermi Energy Question..Free electrons??

A quick question on the Fermi energy.

From a 3D cubic well, one can derive an expression for the Fermi energy of a solid:

Ef = h^2/2m . (3.pi^2.N/V)^2/3


Now, I have come across an expression where N/V, electrons per volume, is replaced by density over mass, times no of FREE electrons. Why is it the FREE electrons tho?? I thought the fermi energy was the highest occupied energy of the electrons at 0 K, which would include the bound electrons (in the ion core say) and the free valence electrons?

Perhaps this is because the formula above is derived from a free electron gas?

Hope someone can enlighten me on this, Cheers!
 
Physics news on Phys.org


The valence electrons in a metal maybe modeled as a gas of electrons. Fermi energy or surface is relevant to the description of the valence electrons only. Bound electrons take no part in the metallic properties (usually).

It so happens that the effective excitations (quasi-particles) due to the interaction of the valence/free electrons resembles the original free electrons in the electron-gas model. This result is known as the Landau Fermi Liquid theory. So one can substitute these interacting electrons with the free ones. Only the mass of these new "electrons" also called quasi-particles is different from the original free electrons.

Hope I've not left you in more confusion. Should wiki/google "Fermi Liquid" theory.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 0 ·
Replies
0
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 21 ·
Replies
21
Views
81K