Quick force on the fulcrum of a lever?

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SUMMARY

The discussion centers on calculating the force on the fulcrum of a lever, specifically in the context of a rowing oar. The input force (Fin) is 80 N, and the output force (Fout) is 21.5 N. The net force acting on the oar is determined by the difference between Fin and Fout, resulting in a force of 58.5 N directed towards Fout. Participants emphasize the importance of balancing forces on the oar and clarify that the forces Fin and Fout act in the same direction, leading to a summation for the fulcrum force.

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  • Understanding of Newton's Third Law of Motion
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Homework Statement



I have a lever problem, i wish to find the force on the fulcrum; how do i determine this force?

http://www.UploadYourImages.com"

Fin = 80 N
Fout= 21.5 N

(yes, usually a lever is supposed to increase your power, but it represents a rowing oar)
 
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No a lever does not increase your power, it increases your force. Power is W/t, and a machine cannot increase the work input. In reality all machines reduce the work since some energy is lost to friction.

But to answer your question, first realize that "Fout" is the force from the oar on the water.

Now you need to determine all the forces that are ON the oar. (Think Newton's 3rd).

Then assume all forces on the oar are balanced (assuming the boat is not accelerating, much).
 
so its just basically the difference between Fin and Fout. Thus in my case, the force on the oar would be Fin-Fout=58.8N; is that right?
 
58.N in the direction of Fout i should say?
 
Last edited:
anyone have an answer for this?
 
Yes, according to your diagram I would say the difference between Fin and Fout is the force on the fulcrum. But in my experience with oars, I would say Fin and Fout point in the same direction, hence it's the sum. Think only of the forces acting on the oar. Not on the water.
 

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