Quick Inner Product Space Question

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SUMMARY

The discussion centers on finding a scalar \( a \) such that the integral \( \int_{-1}^1 a^{2} \, dx = 1 \). The participant suggests that \( a = \frac{1}{\sqrt{2}} \) is a valid solution. Another participant confirms this interpretation, indicating agreement with the proposed answer.

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mmmboh
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Is the first part of this question saying find a scalar a such that [tex]\int_{-1}^1 \! a^{2} \, dx \, =1 \,?[/tex]
In that case I believe 1/20.5 is an answer...or am I reading the notation wrong?

Thanks.
 
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Hey mmmboh,

I would say you are correct.
 

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