Quick Linear Algebra Proof: Why is A^T nonsingular if A is nonsingular?

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SUMMARY

The discussion centers on proving that if matrix A is nonsingular, then its transpose A^T is also nonsingular, and that the inverse of A^T is the transpose of the inverse of A, expressed as (A^T)^(-1) = (A^(-1))^T. Participants utilized the property of transposition of products, (AB)^T = (B^T)(A^T), to manipulate the equations. The conclusion reached is that A^T*(A^T)^(-1) equals the identity matrix I, confirming the nonsingularity of A^T.

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Homework Statement



Prove that if A is nonsingular then A^T is nonsingular and

(A^T)^(-1) = (A^(-1))^T

Homework Equations



(AB)^T = (B^T)(A^T)



The Attempt at a Solution



Step 1: Multiply both sides by B^T

B^T * (A^T)^(-1) = B^T * (A^(-1))^T

B^T * (A^T)^(-1) = (A^(-1)*B)^T

(A^(-1)*B)^T = (A^(-1)*B)^T

I feel that my last step is wrong. Any suggestions would be helpful.

I was also noticing that if I take just the right side of the equation and do this

A^T*(A^(-1))^T = (A^(-1)*A)^T

= I^T = I

which suggests that the left side has to equal I if I multiply it by A^T as well so

A^T*(A^T)^(-1) = I

which makes sense just looking at it.

Thanks!
 
Last edited:
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Start from A*A^(-1)=I. Now take the transpose of both sides and use your relevant equation. Stare at it for a while and figure out what it means.
 

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