Quick Quantum Mechanics Q about basis

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SUMMARY

The discussion centers on the properties of a complete and orthonormal basis in quantum mechanics, specifically regarding the expression Ʃ(j) and its relation to . It is established that if |k> and |i> are elements of the orthonormal basis, then equals 0 when k ≠ i due to the orthonormality condition. The insertion of the identity operator, represented by Ʃ(j) |j> PREREQUISITES

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  • Familiarity with Dirac notation and inner product notation in quantum mechanics.
  • Knowledge of the identity operator in the context of quantum states.
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bon
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Homework Statement



Suppose we have a system and that {|a>, |b>, ...} is a complete and orthonormal basis for the system

Am i right in thinking Ʃ(j) <k|j><j|i> = <k|i> = 0 unless k=i?

In other words, does the LHS expression equal the middle one because Ʃ(j) |j><j| is just the insertion of the identity and we can put it in anywhere?

Homework Equations





The Attempt at a Solution



I've explained my attempt above.

Thanks!
 
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bon said:

Homework Statement



Suppose we have a system and that {|a>, |b>, ...} is a complete and orthonormal basis for the system

Am i right in thinking Ʃ(j) <k|j><j|i> = <k|i> = 0 unless k=i?

In other words, does the LHS expression equal the middle one because Ʃ(j) |j><j| is just the insertion of the identity and we can put it in anywhere?

Homework Equations





The Attempt at a Solution



I've explained my attempt above.

Thanks!

You need to say what |k> and |i> are. If they are elements of the orthonormal basis then if k≠i, <k|i>=0, just because the basis is orthonormal and that's what the 'normal' part means. No need to insert the identity anywhere.
 
Dick said:
You need to say what |k> and |i> are. If they are elements of the orthonormal basis then if k≠i, <k|i>=0, just because the basis is orthonormal and that's what the 'normal' part means. No need to insert the identity anywhere.

Thanks, sorry I wasn't clear. |k> and |i> are elements of the orthonormal basis. And I know that this means <k|i>=0 if k doesn't equal i. It's just that (as part of a larger calculation) I have arrived at the expression

Ʃ(j)<k|j><j|i> (where |j> is also an element of the orthnormal basis) and just wanted to check this equals <k|i>. Am I correct in thinking it does?

Thanks again
 
bon said:
Thanks, sorry I wasn't clear. |k> and |i> are elements of the orthonormal basis. And I know that this means <k|i>=0 if k doesn't equal i. It's just that (as part of a larger calculation) I have arrived at the expression

Ʃ(j)<k|j><j|i> (where |j> is also an element of the orthnormal basis) and just wanted to check this equals <k|i>. Am I correct in thinking it does?

Thanks again

Sure, if j sums over ALL of the elements of the orthonormal basis.
 

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