Quick question about a small problem

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Homework Help Overview

The discussion revolves around solving the equation 840 + 1.5v2.4 - 3.6v1.4 = 0, which is derived from the derivative of a function related to velocity. Participants are exploring methods to find solutions and clarifying the correctness of the derivative.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss potential methods for solving the equation, including Newton's method. There is also a focus on verifying the derivative's correctness, with questions raised about possible errors in the derivation process.

Discussion Status

The discussion is active, with participants sharing insights and questioning assumptions about the derivative. Some guidance has been offered regarding the nature of the roots of the equation, suggesting that it may not have positive real roots.

Contextual Notes

There are indications of confusion regarding the derivative's accuracy, as one participant references a discrepancy noted by Wolfram Alpha. Additionally, there is mention of fatigue affecting the original poster's ability to solve the problem.

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Homework Statement



In my work I am stuck at this equation:
840+1.5v^{2.4}-3.6v^{1.4}=0

I am looking for a quick, easy way to solve this.
Any suggestions? I am kinda tired right now and nothing comes to my mind except maybe Newtons method?
 
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Okay, so this equation comes from the derivative of

s(x)=\frac{600v}{1.4+0.0025*v^{2.4}}

But Wolfram Alpha tells me the derivative is wrong? Oo
What did I do wrong?

s'(x)=\frac{600(1.4+0.0025v^{2.4})-600v(0.006v^{1.4})}{(1.4+0.0025*v^{2.4})^{2}}

s'(x)=\frac{840+1.5v^{2.4}-3.6v^{1.4}}{(1.4+0.0025*v^{2.4})^{2}}
 
Last edited:
Elpinetos said:
Okay, so this equation comes from the derivative of

s(x)=\frac{600v}{1.4+0.0025*v^{2.4}}

But Wolfram Alpha tells me the derivative is wrong? Oo
What did I do wrong?

s'(x)=\frac{600(1.4+0.0025v^{2.4})-600v(0.006v^{1.4})}{(1.4+0.0025*v^{2.4})^{2}}

s'(x)=\frac{840+1.5v^{2.4}-3.6v^{1.4}}{(1.4+0.0025*v^{2.4})^{2}}

##v \times v^{1.4} = v^{2.4}##, not ##v^{1.4}##.
 
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Elpinetos said:

Homework Statement



In my work I am stuck at this equation:
840+1.5v^{2.4}-3.6v^{1.4}=0

I am looking for a quick, easy way to solve this.
Any suggestions? I am kinda tired right now and nothing comes to my mind except maybe Newtons method?

A simple plot of ##840+1.5v^{2.4}-3.6v^{1.4}## shows that the equation has no positive real roots and hence has no real roots at all.
 
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Thanks, I overlooked the v
 

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