- #1

binbagsss

- 1,266

- 11

## Homework Statement

please see attached, I am stuck on the second inequality.

## Homework Equations

attached

## The Attempt at a Solution

I have no idea where the ##2/\pi## has come from, I'm guessing it is a bound on ##sin \theta ## for ##\theta## between ##\pi/4## and ##0## ?

I know ##sin \theta \approx \theta ## for small ##\theta## so we could bound it to ##\pi/4## since ##sin ## increases in this range ## 0, \pi /4 ##, however that would be a stronger approximation , loosing the actual integration over ##\theta ## which is clearly not what has been done.

Many thanks in advance.