Quick question I'm having trouble with (partial fraction integration)

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SUMMARY

The discussion clarifies the rules of partial fraction decomposition in calculus, specifically addressing the distinction between linear factors and irreducible quadratic factors in the denominator. When decomposing fractions like 3/[(x - 1)(x² + 1)], the correct form includes both linear and quadratic terms, resulting in A/(x - 1) + (Bx + C)/(x² + 1). Conversely, for purely linear factors such as 3/[(x - 1)(x - 2)], the decomposition simplifies to A/(x - 1) + B/(x - 2). Additionally, repeated linear factors require a different approach, exemplified by 5/[(x - 1)²] which decomposes to A/(x - 1) + B/(x - 1)².

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Ok, so why do some answers contain an A/something + (Bx + C)/something and others contain just an A/something + B/something.

I hope someone knows what I'm talking about!
 
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Yes, I know what you're talking about. It depends whether the factors in the denominator are linear factors or irreducible quadratic factors.

For example, with 3/[(x - 1)(x2 + 1)], the x - 1 factor in the denominator is a linear factor (x is to power 1) and x2 + 1 is an irreducible quadratic. The decomposition would look like this:
3/[(x - 1)(x2 + 1)] = A/(x - 1) + (Bx + C)/(x2 + 1)

To reduce 3/[(x - 1)(x - 2)], both factors in the denominator are linear factors, so the decomposition would look like this:
3/[(x - 1)(x - 2)] = A/(x - 1) + B/(x - 2)

If you have repeated linear factors, such as 5/[(x - 1)2, things are a little different and the decomposition would be this:
5/[(x - 1)2 = A/(x - 1) + B/(x - 1)2

Hope that helps.
 
Thank's Mark, that makes complete sense. I was confused when the seemingly random x would tag onto an A or B term and i had no idea why. Thanks again for clarifying.
 

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