Quiz question: Who Dies If 'E' Pushes The Stone?

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SUMMARY

The discussion centers on a physics-based quiz question regarding the dynamics of a seesaw mechanism involving stones labeled A, B, C, and D. Participants analyze the potential outcomes of a stone being pushed and its impact on the other stones. Key conclusions indicate that stone A is likely to be hit, while stones B and C are safe due to the mechanics of momentum and the configuration of the notch over stone D. The calculations of the circumference of the notched stone and the hypotenuse distance are suggested as critical components for understanding the scenario.

PREREQUISITES
  • Understanding of basic physics principles, particularly momentum and energy transfer.
  • Familiarity with geometric calculations, including circumference and hypotenuse.
  • Knowledge of seesaw mechanics and equilibrium.
  • Ability to analyze dynamic systems and predict outcomes based on initial conditions.
NEXT STEPS
  • Research the principles of momentum in physics, focusing on collisions and energy transfer.
  • Learn how to calculate the circumference of various shapes, specifically notched objects.
  • Study the mechanics of seesaws and their equilibrium states in physics.
  • Explore dynamic system analysis techniques to predict outcomes in similar scenarios.
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in problem-solving within dynamic systems will benefit from this discussion.

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swampwiz said:
https://scontent-arn2-1.xx.fbcdn.net/v/t1.0-9/31131486_10155149285526260_4418766605865975808_n.jpg?_nc_cat=0&oh=53840620f886c5dab249cc2a8ff1010b&oe=5B4E8CA6
What is your answer and why?
 
russ_watters said:
What is your answer and why?

I think that if anything, A gets hit, but the stone could roll all the way through (besides, A could duck). I'm presuming that the notch fits perfectly over D, and there would be only horizontal momentum going to the seesaw, and with the other stone being heavier (i.e., no notch), it would not crush C, and would vault over the other stone (because of the kinetic energy), clearing B as well.
 
swampwiz said:
I think that if anything, A gets hit, but the stone could roll all the way through (besides, A could duck). I'm presuming that the notch fits perfectly over D, and there would be only horizontal momentum going to the seesaw, and with the other stone being heavier (i.e., no notch), it would not crush C, and would vault over the other stone (because of the kinetic energy), clearing B as well.

To start it off, there is probably a way to calculate the circumference of that notched stone. Then calculate the distance of that hypotenuse.
 

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