Radial and Circumferential Components in terms of t

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Homework Help Overview

The problem involves determining the radial and circumferential components of acceleration for a particle described by the position vector \(\vec{R} = (t + \sin t) \hat{i} + (t + \cos t) \hat{j}\) as a function of time \(t\). The context is centered around concepts of motion in a plane, specifically relating to polar coordinates and acceleration components.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the difficulty of expressing the radial distance \(r\) and the angle \(\theta\) in terms of \(t\). There is an attempt to derive \(r\) using the formula \(r = \sqrt{x^2 + y^2}\), but complications arise with differentiation. Questions are raised about the distinction between tangential and circumferential components of acceleration.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of acceleration components. Some guidance has been offered regarding the unit vector in the radial direction, but clarity on the definitions and relationships between the components remains a topic of exploration.

Contextual Notes

There is a noted confusion regarding terminology, particularly between tangential and circumferential components of acceleration. Participants are also grappling with the challenge of expressing angular components in terms of time.

Trapezoid
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Homework Statement



Let [itex]\vec{R} = (t + \sin t) \hat{i} + (t + \cos t) \hat{j}[/itex] denotes at time t the position of a moving particle. Determine the radial and circumferential components of acceleration as a function of t.


Homework Equations



[tex]v_r = \dot{r}[/tex]
[tex]v_{\theta} = r\dot{\theta}[/tex]


The Attempt at a Solution



I tried to write r in terms of t using [itex]r = \sqrt{x^2 + y^2}[/itex], but the derivative was complicated. I do not know how to write [itex]\theta[/itex] in terms of t. We were asked to determine the tangential and normal components of acceleration in the previous part of the question, but I do not see how they will avail me. Could anybody point me in the right direction?

Thanks,
Trapezoid
 
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Hi Trapezoid! :smile:
Trapezoid said:
Determine the radial and circumferential components of acceleration as a function of t.

The tangential component (i assume that's what they mean by circumferential) is just d|v|/dt :wink:

(and you know the magnitude and direction of the total acceleration)
 
Hi tiny-tim,

It is my understanding that the tangential and circumferential components are different. When I say the circumferential component of acceleration, I refer to the acceleration in the direction of [itex]\theta[/itex], ie: the change in the rate of change of [itex]\theta[/itex]. I'm having trouble finding [itex]\theta[/itex] as a function of t..

Does that make sense? Have I misunderstood?

Thanks,
Trapezoid
 
Trapezoid said:
When I say the circumferential component of acceleration, I refer to the acceleration in the direction of [itex]\theta[/itex], ie: the change in the rate of change of [itex]\theta[/itex]. I'm having trouble finding [itex]\theta[/itex] as a function of t..

ah, not a terminology I've come across before :redface:

ok, then r is the position, r'' is the acceleration, r''.r/|r| is the radial component, and what's left is the circumferential component :smile:
 
Thanks tiny-tim,

Let me make sure that I understand correctly. Is [itex]\frac{r}{|r|}[/itex] the unit vector for motion in the radial direction?
 
yes, the unit vector in the radial direction is r/|r|
 

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