Radial visualization & spring forces

AI Thread Summary
Radial visualization for 3-dimensional and 8-dimensional samples can be derived using trigonometric functions, specifically cosine and sine. For 3-dimensional samples, the formulas involve constants K1 and K3, while the 8-dimensional formulas incorporate additional constants K2, K4, K5, K6, K7, and K8. The constants sqrt(2)/2, sqrt(3)/2, or 1/2 appear in the final expressions due to the values of sine and cosine at specific angles. Understanding these relationships helps in simplifying the equations as angles increase. Mastery of these concepts is crucial for effectively tackling problems in radial visualization.
jst
Messages
28
Reaction score
0
Hi, I am taking a Data Mining course and have this problem in radial visualization. To complete this problem, we use some physics formulas, which I really do not understand.

Derive formulas for radial visualization of:

a. 3-dimensional samples

b. 8-dimensional samples

Homework Equations



Here's what our notes have:
http://glomawr.com/radialvisualization.jpg

The Attempt at a Solution



I thought it would be very similar to the example in the notes so for part A I did:

x = (K1 - K3 - K5 - K7)/(K1 + K2 + K3 + K4 + K5 + K6 + K7 + K8)
y = (K2 - K4 - K6 - K8)/(K1 + K2 + K3 + K4 + K5 + K6 + K7 + K8)

and part B, I did:

x = (K1 - K3)/(K1 + K2 + K3)
y = (K2)/(K1 + K2 + K3)

I am told: "sqrt (2)/2, or sqrt(3)/2 or 1/2 are in the final expressions because of trig functions: sin and cos for angles of 30, 45 or 60 degrees."

I'm really lost, our book doesn't have what I need it sort of assumes that this example was enough, but I'm lost. I really don't need the solution, as much as an explanation of how to do it myself.

Thanks a lot,

Jason
 
Last edited by a moderator:
Physics news on Phys.org
The formulas for radial visualization of 3-dimensional and 8-dimensional samples can be derived using the trigonometric functions cosine (cos) and sine (sin).For 3-dimensional samples, the formula is:x = cos(α) * K1 - sin(α) * K3y = sin(α) * K1 + cos(α) * K3where α is the angle measured in radians and K1 and K3 are constants. To derive the formula for an 8-dimensional sample, we use the same principles but with different constants. The formula is:x = cos(α) * (K1 - K3 - K5 - K7) - sin(α) * (K2 - K4 - K6 - K8)y = sin(α) * (K1 - K3 - K5 - K7) + cos(α) * (K2 - K4 - K6 - K8)where again, α is the angle measured in radians and K1, K2, K3, K4, K5, K6, K7, and K8 are constants. The constants are determined by the sample data points.The constants sqrt (2)/2, or sqrt(3)/2 or 1/2 are in the final expressions because of the trigonometric functions. As the angle increases, the sine and cosine values approach these constants, which allows us to simplify our equations. For example, if the angle is 45 degrees (1.57 radians), then cos(1.57) = 0.707 and sin(1.57) = 0.707, so sqrt (2)/2 is used in the final expression.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
19
Views
3K
Replies
2
Views
4K
Replies
15
Views
3K
Replies
4
Views
2K
Replies
4
Views
3K
Replies
2
Views
2K
Replies
7
Views
3K
Back
Top