Radiationless de-excitation - how does radiative heating work?

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Radiative heating involves exciting electrons to higher energy states, while heat energy is associated with molecular vibrations. The concept of radiationless de-excitation suggests that an excited electron can transfer its energy to a molecule, leading to de-excitation. This process can be understood through photon-phonon coupling, which describes how optical absorption contributes to heating. Many resources on solid-state physics and radiation heat transfer explore these interactions in detail. Understanding these models helps reconcile the relationship between electron excitation and molecular vibrations in the context of heat energy.
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You typically hear of radiative heating as exciting an electron to a higher state in an atom or molecule, but heat energy is the excessive vibration of a molecule. How do you reconcile these two models? I've heard of something called radiationless de-excitation whereby the electron passes its energy to the molecule and becomes de-excited. Is this the correct way to think about standard radiative heating?
 
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If I understand you correctly, you are asking about photon-phonon coupling as a description of optical absorption and heating. I'm not an expert on this, but many solid-state and radiation heat transfer books give an account.
 

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