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Radical/Fraction question correct?

  1. Feb 13, 2005 #1
    Ok well this is the question. SQRT3/2 / 1/2 Its on of those fractions stacked onto another fraction questions, except with the first fraction having a radical in the numerator. I ended up getting SQRT3 + 4/2. Is this right?
     
  2. jcsd
  3. Feb 13, 2005 #2

    dextercioby

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    Use paranthesis to explain what you meant.Is it:[tex] \sqrt{\frac{\frac{3}{2}}{\frac{1}{2}}} [/tex] ?

    Daniel.
     
  4. Feb 13, 2005 #3
    I think he means:
    [tex] \frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}} [/tex]

    Maybe?
    -EP
     
  5. Feb 13, 2005 #4

    dextercioby

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    In any of the 2 cases,why is there a "+" in the final answer...????

    Daniel.
     
  6. Feb 13, 2005 #5
    Yes I mean what Eroph wrote. Umm I multiplied them by reversing the denominator and I did a sorta cross multiplying thing. Did I do it wrong?
     
  7. Feb 13, 2005 #6
    Lol I made a mistake and I was adding or something. Is the answer (2SQRT3) / 2?
     
  8. Feb 13, 2005 #7

    dextercioby

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    Yep,you can simplify through that "2" and bring the result to a simpler form.

    Daniel.
     
  9. Feb 13, 2005 #8
    So then the final answer would just be SQRT3 then?
     
  10. Feb 13, 2005 #9

    dextercioby

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    Of course it would...

    Daniel.
     
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