Radius of Circular Path Affected by Magnetic Force: Increase or Decrease?

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SUMMARY

The discussion centers on the relationship between the radius of an electron's circular path and its velocity when influenced by a magnetic field. The equation governing this relationship is F(m) = mv²/r, where F(m) is the magnetic force, m is mass, v is velocity, and r is the radius. As the velocity of the electron increases, the radius of its circular path also increases due to the quadratic relationship of velocity in the equation. The magnetic force does increase with velocity, but the squared term of velocity dominates, leading to an overall increase in radius.

PREREQUISITES
  • Understanding of classical mechanics, specifically centripetal motion
  • Familiarity with electromagnetic theory, particularly the Lorentz force
  • Knowledge of the equations governing circular motion
  • Basic grasp of vector quantities in physics
NEXT STEPS
  • Study the Lorentz force law in detail to understand its implications on charged particles
  • Explore the concept of magnetic flux density (B) and its effects on charged particles
  • Investigate the relationship between velocity and radius in circular motion under varying forces
  • Learn about the applications of charged particle motion in magnetic fields, such as in cyclotrons
USEFUL FOR

Students of physics, particularly those focusing on electromagnetism and classical mechanics, as well as educators seeking to clarify concepts related to charged particle dynamics in magnetic fields.

Gunman
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Homework Statement


An electron moves in a circular path in a vacuum under the influence of a magnetic field perpendicular to and into the paper.If there is another electron which moves with a higher speed in a circular path in the same B-field, state and explain how each of the following will be affected as compared to the first electron?
(c) The radius of the circular path


Homework Equations


F = Bqv
B = flux density
q = charge
v = velocity of the charge


The Attempt at a Solution



F(m) = Bqv
Since F(m) causes the centripetal acceleration of electron
F(m) = Bqv = mv^2/r
r = mv/Bq
Therefore it can be concluded that r increases as v increases?

But how can this be case as,
F(m) = Bqv, and F(m) increases as velocity of the charge increases
If F(m) increases, r would decrease as it is inversely proportional to F
in the equation F(m) = mv^2/r.

So would r increase or decrease if a faster electron moves in a circular path in a vacuum under the influence of a magnetic field perpendicular to and into the paper.
 

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Gunman said:

Homework Statement


An electron moves in a circular path in a vacuum under the influence of a magnetic field perpendicular to and into the paper.If there is another electron which moves with a higher speed in a circular path in the same B-field, state and explain how each of the following will be affected as compared to the first electron?
(c) The radius of the circular path


Homework Equations


F = Bqv
B = flux density
q = charge
v = velocity of the charge


The Attempt at a Solution



F(m) = Bqv
Since F(m) causes the centripetal acceleration of electron
F(m) = Bqv = mv^2/r
r = mv/Bq
Therefore it can be concluded that r increases as v increases?

But how can this be case as,
F(m) = Bqv, and F(m) increases as velocity of the charge increases
If F(m) increases, r would decrease as it is inversely proportional to F
in the equation F(m) = mv^2/r.

So would r increase or decrease if a faster electron moves in a circular path in a vacuum under the influence of a magnetic field perpendicular to and into the paper.
You have clearly put a lot of thought into this question, perhaps a little too much :wink:. Consider your final equation,

F = \frac{mv^2}{r}

And your final comment,
Gunman said:
If F(m) increases, r would decrease as it is inversely proportional to F
You are correct that the magnetic force increases, but you forget that the speed v has also increased. Notice that the speed is raised to the second power and therefore will have a much greater effect on the magnetic force that the radius since the radius is only raised to the fist power.
 

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