Radius of hellical chain (radius of path of electron)?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
4 replies · 2K views
delsoo
Messages
97
Reaction score
0

Homework Statement



here's the question, is my concept correct? the ans is 9.86 cm, but my ans is 13 cm, can anyone tell me which part is wrong?

Homework Equations





The Attempt at a Solution

 
Attachments
  • DSC_0115~3[2].jpg
    DSC_0115~3[2].jpg
    21.7 KB · Views: 512
Physics news on Phys.org
mfb said:
For your formula, you have to take the perpendicular component of the velocity only.

perpendicular velocity is v sin tetha, so i sub all the values to the working above, i would get r=(mv)/(Bq sin 60) , where m=9.1x10^-31 , v= 4.0x10^7 ms^-1 B=2.0x10^-3 T , q=1.6X10^-9C , i would get 0.13m but not 9.86 cm... what's wrong with my working?
 
mfb said:
At one side you did use the angle, but I think at the other side you did not.

what do u mean? can you expalin more detail?