Raising Barrel w/ Pipes: Min Force Required | Physics Homework

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SUMMARY

The discussion focuses on calculating the minimum horizontal force required to raise a 100 kg barrel using two horizontal pipes with a diameter of 0.50 m. The solution involves applying Newton's laws of motion, particularly the third law, to determine the forces acting on the barrel. By analyzing the geometry of the setup and using trigonometry to resolve the forces along the contact lines between the barrel and the pipes, participants can derive the necessary force exerted by the feet to lift the barrel. The key takeaway is the importance of understanding force components and their relationship to the weight of the barrel.

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  • Understanding of Newton's laws of motion
  • Basic knowledge of trigonometry
  • Familiarity with force diagrams and vector components
  • Concept of static equilibrium in physics
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  • Learn about vector resolution and force components in physics
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This discussion is beneficial for physics students, educators, and anyone interested in mechanics, particularly those studying force interactions in static systems.

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Homework Statement



Michael is trying to raise a barrel using sections of pipe.The three objects are horizontal cylinders resting on level ground. The barrel has a mass of 100 kg and its diameter is 2.0m. Each pipe has a diameter of 0.50 m. What minimum horizontal force must his feet exert on the pipe to raise barrel from the ground? Neglect Friction.


Homework Equations



Newton's first law, Newton's second law, Newton's third law...

The Attempt at a Solution



well, i figure that the pipe in the corner against the wall has no acceleration, but because of Newton's third law exerts a force equal to force applied onto the barrel (force contact). now, I am just confused after where to go now.

i thought about it, and the distance between the two cylinders, pipe and barrel, must 1.5m.

thats as far as i got. PLEASE HELP! D:
 

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Welcome to PF, dragon.
I suggest you draw a line from the center of the barrel to the center of each pipe, passing through the points where the pipes contact the barrel. The force of each pipe on the barrel will be along those two lines and will be partly horizontal and partly vertical. Draw the component of the applied force vector that is along the contact line and calculate its portion of the applied F using trigonometry (you will need the angle of the contact line above horizontal). Then multiply by the appropriate factor to get the vertical component of that force. Double it because you have an equal force from the other side. That should give you a number time F, which is equal to the weight of the barrel. Solve for F.
 

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