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Range of projectile traveling through two points at same elevation

  1. Aug 14, 2006 #1
    "A projectile is fired with an initial velocity [tex]V_o[/tex] such that it passes through two points both a distant h above the horizontal. Show that if the gun is adjusted for a maximum range the separation of the potins is?"

    my work is http://home.earthlink.net/~suburban-xrisis/projectile.pdf" [Broken]

    does it look correct?
    Last edited by a moderator: May 2, 2017
  2. jcsd
  3. Aug 16, 2006 #2

    Meir Achuz

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    h/A does NOT equal tan 45. Just look at your picture to see this.
    Find h in terms of A by using the eqs. A=v_0 t cos45 and
    h=v_0 t sin45-(1/2)gt^2.
  4. Aug 16, 2006 #3
    I'm not sure why they would not be equal.

    Opposite/Adjacent = tan(theta)

    The side opposite to the angle is h
    The side Adjacent to the angle is A

    so the equation should read: tan(45)=h/A

    and why would I want to get h in terms of A? Dont I want A in terms of h?

    I made up the variable A so I that I could get A in terms of h and subtract it from the max range.
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