Rate of change (surface area/radius)

[321study]

Homework Statement
I am 99% positive I did a) correctly, as the answer is correct according to the answer in the back of my textbook. However, I cannot do b).
The question: A spherical balloon is being inflated. Find the rate of change of the surface area with respect to the radius when:

a) The radius is 5cm
b) The surface area is 200cm²

The attempt at a solution

a) 8\pi*5cm
=125.66 cm²/cm (or 40\pi cm²/cm)

b) I am unsure of what to do for this. Is it something like:

\sqrt{}200/4\pi

=3.9894

And then do something else, which I don't know what that is.

The answer to this question, according to the book, is 100.27cm²/cm

Sorry if the equations don't look very clear. This is my first post and I will learn how to write it all up neatly when I am not so tired.

 

[Hootenanny]

Welcome to Physics Forums.

Since you have solved the first part, I assume that you have worked our that

\frac{dS}{dr} = 8\pi r\;.

Now, what you need to ask yourself if: "How is the radius related to the surface area?".

 

[process91]

There's an excellent video here:
http://press.princeton.edu/video/banner/

which, I think, should give you what you need to know. It's 50 minutes into video 5, and you shouldn't need to watch any of the others in order to follow the explanation (although they are all a good intuitive primer to calculus). Professor Banner covers related rates problems for about 20 minutes, and it should address your question.

 

[HallsofIvy]

I presume you know that the surface area of a sphere of radius r is A= 4\pi r^2. That gives, of course, dA/dr= 8\pi r which is where you got "8π*5cm" for (a).

For (b), instead of being given r, you are given A= 200. Solve 4\pi r^2= 200 for r, then do it the same as (a).

 

[321study]

Unfortunately I won't be able to view the video as it will take a while to download and I've got to get going to school for an excursion. Thank you though.

So if I try:

200*4pi

= 2513.27

Get the square root of that makes 50.1325

Multiple by 2 for some reason? Makes 100.265. Rounded off gives 100.27. I am pretty sure I tried this method before, however I got 100.29 (rounding error) and I forgot how I did it all. Nevertheless, I don't really understand why I must multiple my answer by 2.
Thanks for all your help so far.

 

[process91]

So if I try:
200*4pi
= 2513.27
Get the square root of that makes 50.1325

Try to solve for r again. Look at the equation 4\pi r^2= 200, make sure you're correctly solving for r. Then, once you have r, you can use your derivative equation to get the answer.

 

[321study]

Ok I did it.

Here is my working:

4\pir² = 200
r² = 200/4\pi
r = Square root of 50/\pi

dS/dr = 8\pir
= 8\piSquare root of 50/\pi
= 100.27 cm²/cm

Thanks everyone for all your help