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So I used the equation;

P(air) + 1/2 d(density)v1^2 + pgh(total height of water) = P(air) + 1/2dv2^2 + pgh(from the bottom of the container to the leak)

The equation then simplifies to:

gh(total height) = 1/2V2^2 + gh(from bottom to leak)

V2^2 = 2g(h(total) - h(form bottom to leak))

V2^2 = 2g(h(from leak to top of water))

Since this h is known, I can solve for v.

I Just can't figure out the diameter part.

Any help is appreciated.