Rate of flow of water through a pipe

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SUMMARY

The discussion centers on the relationship between motor power and the rate of water flow through a horizontal pipe. The original power required by the motor is expressed as P = ρAv²*v, where A is the cross-sectional area and v is the velocity of water flow. To increase the flow rate by a factor of n, the power must increase to P1, which is determined to be P1 = n³P. The conclusion drawn is that the ratio of P1 to P is n:1, confirming the correctness of the solution presented.

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Homework Statement



A motor of power P is used to deliver water at a certain rate through a given horizontal pipe. To increase the rate of flow of water through the same pipe n times, the power of the motor is increased to P1. The ratio of P1 to P is?


The Attempt at a Solution



Let the velocity of flow of the water be 'v'.
The power required by the motor P = ρAv2*v, where A is the area of cross section of the pipe. Rate of flow of water, R = Av
P=ρRv2=ρR3/A2

It can be seen that P1=n3P.
The answer given is n:1
What's wrong?
 
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I think there is nothing wrong with your solution :)
 
Thanks!
 

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