Rates of Reaction: Questions Answered

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The discussion addresses three key questions about rates of reaction. The first question highlights that a chemical reaction is most rapid at the start due to the maximum concentration of reactants present. The second question suggests that increasing the rate of dissolving sugar can be achieved by raising the temperature, stirring faster, or using a catalyst. The third question explains that an increase in temperature affects both the forward and reverse reaction rates by bringing the system's energy closer to the activation energy, thus altering the equilibrium constant. Additionally, participants seek help with calculating the heat of reaction and activation energy for a specific reaction, indicating a need for more data to solve the problem.
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I have some quick questions that I need some help with:

1.

Why would a simple chemical reaction such as

NO9g) + 1/2O2(g) -----------> NO2(g) most likley be most rapid at the start?

2.

In what ways can the rate of dissolving a lump of sugar be increased? (at least 3)

3.

Finally, what effect would there be on the rate of constant of, forward reaction, and reverse reaction if there was an increase in temperature?
 
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ChemRookie, you are asking us to do your homwork for you. We can't do that.

But we can help if you show what you have tried so far.

At least 2 of the 3 questions are pretty straightforward, and the answers should be in your text. You should be able to answer them without understanding a thing about kinetics. To answer the first question, you must first understand the concept of a reaction rate, and why it is the way it is. Once you get this, #1 is pretty obvious.
 
1) Think about what particles are present at the start - ie the concentration of the reactants are maximum at the start.

2) Look up how surface area : volume ratio affects reaction rate

3) Look up kinetic theory/Boltzman distribution.
 
So...

1) Would the answer be that the chemicals involved in this reaction have a electron configuration in which they easily give off their electrons..therefore, easily react. ? Would it be specific to what chemicals they are, or is there just a rule that reactions are faster at the beginning?

2) obviously one is temperature, possibly also stirring faster? and maybe using a catalyst? (another substance to help it along)


3) for number 3. I know that a forward reaction is a reaction where the concentration increases with time, and a reverse is the other way around. So, how would an increase in temp affect the rate of constant of those 2..well, for a forward reaction, the the concentration would not increase I guess..since the reaction would happen quicker? for a reverse reaction, I guess it would have no affect?
 
#3. The equilibrium constant changes as the temperature varies since the ratio Rate forward/Rate reverse changes, find in your text a relationship/derivation of the equilibrium constant from the rate costants. Also note that an increase in temperature would now facilitate both reactions, since the energy of the system is now closer to the activation energies of both reactions...it is most often the case that the one reaction limited by kinetics will have its rate increased more in a relative sense.
 
one more question, here:

For the reaction

CO + NO2 ----> CO2 + NO the activation energy for the forward reaction is 135kj/mol of CO reacted.

a) determine the heat of reaction
b) from the data given, and the deltaHr for the reaction, determine the activation energy for the reverse reaction.
c) draw and label a potential energy diagram for the reaction

can someone help me with a and b at least..thanks. someone told me I don't have enough data to do the question and looks that way to me too.
 
can anyone answer if I have the neccesary info here? or any help with it

thanks.
 
a) Arrehenius Equation
b) Hess' Law
 
And I would do (c) before doing (b).
 
  • #10
but, I don't have all of these variables.
http://www.shodor.org/UNChem/advanced/kin/arrhenius.html#a

?


the question:
For the reaction

CO + NO2 ----> CO2 + NO the activation energy for the forward reaction is 135kj/mol of CO reacted.

a) determine the heat of reaction

and once I get the answer, how would I get the reverse reaction?
 
  • #11
anybody?

T= 0degcel=293K?
P= 8.314J/mol K
E(a) = 135kj/mol
A= ?
what's the arrhenius constant?

k = -Ea/RT + ln A
 
  • #12
ChemRookie said:
anybody?

T= 0degcel=293K?
P= 8.314J/mol K
E(a) = 135kj/mol
A= ?
what's the arrhenius constant?

k = -Ea/RT + ln A

The T should equals to 273k
 
  • #13
Question 1. According to reaction rate and experimentally approved stated that rate is direct proportion to the concentration.At the initial time there are the highest concentration as long as the reaction took places the concentration gradually decrease simultaneously with rate of reaction.
 
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