Ratio of frequency between heavier and lighter part of composite cord

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The discussion centers on the frequency of a composite cord connected to a vibrating source, confirming that sections A and B vibrate at the same frequency of 100 Hz. Participants clarify that while the frequencies are equal, the wave speeds and wavelengths differ due to the varying densities of the cord's sections. Some suggest the question may be misleading, implying it could be asking for the ratio of wavelengths instead. The importance of recognizing conceptual consistencies in physics is emphasized, highlighting a common misconception in relativity. Understanding these fundamental principles is crucial for mastering the subject.
songoku
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Homework Statement
Please see below
Relevant Equations
v = λ.f
1714016152742.png


Is the answer 1? Because the cord is connected to vibrating source and it vibrates with a frequency of 100 Hz so section A and B have the same frequency

Thanks
 
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songoku said:
Homework Statement: Please see below
Relevant Equations: v = λ.f

View attachment 344025

Is the answer 1? Because the cord is connected to vibrating source and it vibrates with a frequency of 100 Hz so section A and B have the same frequency

Thanks
Either it is a trick question or they meant to ask for the ratio of wavelengths.
 
Yes, the frequencies must be the same. The speed of the waves and the wavelengths will differ.
 
Thank you very much haruspex and Orodruin
 
haruspex said:
Either it is a trick question or they meant to ask for the ratio of wavelengths.
I would not call it a trick question. Realising that something conceptual does not change or when something is trivial is a very important skill in understanding a subject. For example, I keep asking relativity students a question where a muon travels a certain distance in the lab frame before decaying and I want them to tell me how far it travels in its rest frame. I keep asking because I have seen people get it wrong so many times and it illustrates something fundamental.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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