Rationalizing Complex Denominators for Scientists

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To rationalize the complex denominator 1/((i-s)^2), multiplying the numerator and denominator by (i+s)^2 is appropriate. The term "rationalize" is debated, as it traditionally refers to making a denominator rational, but in this context, it also involves converting to standard form. The process results in a real denominator, which can be rational depending on the value of s. The discussion highlights the importance of terminology in mathematical contexts, particularly regarding complex numbers. Ultimately, the goal is to simplify the expression effectively.
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1/((i-s)^2)) how do i rationalize this , would i multpiy top and bottom by
(i+s)^2
 
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cragar said:
1/((i-s)^2)) how do i rationalize this , would i multpiy top and bottom by
(i+s)^2

(rationalize? anyway …)

Yup! :biggrin:
 
k thank-you
 
tiny-tim said:
(rationalize? anyway …)


By the way, what is the proper term? (assuming "rationalize" is not)
 
"Rationalize" is the correct vocabulary for what you wanted.
 


Unit said:
By the way, what is the proper term? (assuming "rationalize" is not)

Hi Unit! Hi symbolipoint! :smile:

Well, "rationalize" means to make rational, which this doesn't, neither in the English nor in the mathematical sense.

It actually puts a complex number into the standard x + iy form, so I'd prefer to say "put into standard form" …

however … now you raise the point, I see that http://hyperphysics.phy-astr.gsu.edu/hbase/cmplx2.html#c2 and others do say "rationalize" … I wonder why? :redface:
 
But it's asking to rationalize the denominator which is achieved. The denominator becomes real, and possibly rational depending on the value of s.
 
For ex. 1/i where i is complex number. By multiplying with i / i you get i / i2 = i / (-1), which makes the denominator real number (also rational) since I can write (-1) as (-1)/1 and the final equation would be i / (-1) / 1. Now the denominator is rational and I rationalize the equation. :smile:

Regards.
 
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