Rationalizing Stability of NF3 and NCl3

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Nitrogen trifluoride (NF3) is stable due to its strong N-F bonds with a bond energy of 278 kJ/mol, while nitrogen trichloride (NCl3) is less stable because its N-Cl bonds have a lower bond energy of 193 kJ/mol. The decomposition of NCl3 into nitrogen (N2) and chlorine (Cl2) releases energy, making it hazardous to handle. The stability of NF3 can be rationalized by comparing the energy released during the formation of its bonds versus the energy required to break them. Calculating the total energy for both compounds can provide insight into their stability. Understanding bond energies is crucial for explaining the differing stability between NF3 and NCl3.
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Homework Statement


Nitrogen trifluoride, NF3, is relatively stable toward decomposition to its elements. In contrast, NCl3 can be dangerous to work with because of its tendency to decompose to N2 + Cl2, Use bond energies to rationalize.


Homework Equations



Bond energies for N-F is 278 kJ/mol, N-Cl is 193 kJ/mol, N≡N is 942 kJ/mol, Cl-Cl is 240 kJ/mol and F-F is 154 kJ/mol.


The Attempt at a Solution



I don't really know what we are supposed to be explaining. Rationalizing the formation of N2 and Cl2 has more to do with attraction than bonding energies right? I'm so lost :(
 
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i think its because when the bonds decompose, it releases energy, given off in some form...that could make it dangerous...i have not done the calculations, you should try that...see if NCl3 has more or less energy than N2 + Cl2
 
link2110 said:
see if NCl3 has more or less energy than N2 + Cl2

And do the same for NF3. It doesn't have to give the answer, but that's the most obvious thing to try.
 
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