- #1

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Some ideas I have is let a = x+y and b = x-y and apply triangle inequity

Could anyone give me some direction?

Thanks

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- Thread starter Askhwhelp
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- #1

- 86

- 0

Some ideas I have is let a = x+y and b = x-y and apply triangle inequity

Could anyone give me some direction?

Thanks

- #2

Ray Vickson

Science Advisor

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Some ideas I have is let a = x+y and b = x-y and apply triangle inequity

Could anyone give me some direction?

Thanks

Sure: just use your ideas above and see where they lead.

- #3

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|2x| = |a+b| <= |a| + |b|

|2y| = |a- b| <= |a| + |b|

So |2x| + |2y| <= 2(|a| + |b|)

Divide both sides by 2, we get

|x|+ |y| <= |a| + |b|

Is this right way?

Thanks

- #4

Dick

Science Advisor

Homework Helper

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|2x| = |a+b| <= |a| + |b|

|2y| = |a- b| <= |a| + |b|

So |2x| + |2y| <= 2(|a| + |b|)

Divide both sides by 2, we get

|x|+ |y| <= |a| + |b|

Is this right way?

Thanks

Sure, that's a fine proof.

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