Rearranging an SUVAT Equation: Solving for Time

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SUMMARY

The discussion focuses on rearranging the SUVAT equation, specifically solving for time (t) in the equation s = -0.5at². Participants emphasize the importance of understanding algebraic manipulation, particularly in handling negative factors. The correct approach involves multiplying both sides of the equation by -2/a to isolate t. The conversation highlights the necessity of revisiting basic algebra concepts for effective problem-solving in physics.

PREREQUISITES
  • Understanding of SUVAT equations in physics
  • Basic algebra skills, including manipulation of equations
  • Familiarity with negative numbers in mathematical contexts
  • Knowledge of solving quadratic equations
NEXT STEPS
  • Review basic algebra techniques for rearranging equations
  • Study the application of SUVAT equations in kinematics
  • Learn about quadratic equations and their solutions
  • Practice problems involving negative factors in equations
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone needing to refresh their algebra skills for solving equations.

Physics55555
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Hello everyone,

Please can someone help me rearrange this equation to make t the subject:

upload_2016-4-18_18-35-35.png
Relevant equations:
upload_2016-4-18_18-35-45.png
My attempt at a solution:
upload_2016-4-18_18-36-25.png


Thank you all for you help
 
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Physics55555 said:
Hello everyone,

Please can someone help me rearrange this equation to make t the subject:

View attachment 99318

Relevant equations:
View attachment 99319
My attempt at a solution:
View attachment 99320

Thank you all for you help
Not such good Algebra.
0.5 is a factor. It's not added or subtracted.

You start with
##s=-\frac12 at^2 ##

Multiply both sides by ##\displaystyle \ -\frac2a\ ##
 
You probably should take a few minutes to review basic algebra before going any further with physics. :wink:
 
lol, thanks guys. It's been years since I've done this kind of stuff! I've totally forgotten what to do when there's a negative number involved.

Appreciate the help @SammyS and @SteamKing
 
Physics55555 said:
lol, thanks guys. It's been years since I've done this kind of stuff! I've totally forgotten what to do when there's a negative number involved.

Appreciate the help @SammyS and @SteamKing
You're welcome.

It's more a matter that the numbers are all multiplied, rather than that there is a negative.
 

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