- #1

BogMonkey

- 76

- 0

1.)

**v = u + at**

2.)

**v^2 = u^2 + 2as**

3.)

**s = ut + 1/2(at^2)**

v = final velocity, u = initial velocity, a = acceleration, t = time, s = displacement

In an example my physics teacher uses the equation

**x = x0 + (v^2-u^2)/2a**

I'm assuming he derived that from the second equation I listed but I can't figure out why (v^2-u^2) is divided by 2a. When I rearrange that equation I get

**s = v^2 - y^2 - 2a**

Am I just using incorrect algebra or is that a different equation altogether?