Recoil energy from neutrino question

  • Thread starter Thread starter Exulus
  • Start date Start date
  • Tags Tags
    Energy Neutrino
Click For Summary

Homework Help Overview

The discussion revolves around a problem involving the decay of an Ar37 atom through electron K capture into a Cl37 atom and a neutrino, along with a gamma ray emission. Participants are tasked with calculating the recoil energy of the Cl37 atom upon the emission of the neutrino, given specific energy values and mass differences.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the Q value and apply linear momentum conservation but expresses confusion about how to proceed. Some participants question whether the X-ray emission has been considered in the calculations.

Discussion Status

There is a note that the problem has been solved, with one participant indicating that the X-ray emission was not necessary for the solution. However, the details of the resolution are not fully explored in the discussion.

Contextual Notes

The original poster mentions a lack of clarity on how to approach the problem and expresses frustration over not reaching the expected answer. There is also a note about the need to format the post correctly, indicating potential constraints in the discussion format.

Exulus
Messages
50
Reaction score
0
Hi guys,

I've been struggling with this problem for a while now and can't seem to get anywhere with it. Roughly speaking:

We are given that an Ar37 atom decays through electron K capture into a Cl37 atom and a neutrino, plus a gamma ray of wavelength 4.2 Angstroms. The binding energy of the K capture is 3KeV and the mass difference between Ar37 and Cl37 is 816KeV. We've been asked to calculate the recoil energy of the Cl37 atom when the neutrino is emitted. We know the answer is 9.6eV but can't seem to get anywhere near it!

So far I've calculated the Q value to be 813KeV through the mass difference minus the binding energy of the captured electron. I've tried using linear momentum conservation knowing that the energy of the neutrino is E = pc. However, I can't even see how to begin.

Can anyone offer any starters? I've tried searching everywhere :( Thanks. I believe these are all the values we need to calculate it, but i am at a loss on what to do!
 
Last edited:
Physics news on Phys.org
Hi guys (originally posted in the nuclear forum but since found this one),

I've been struggling with this problem for a while now and can't seem to get anywhere with it. Roughly speaking:

We are given that an Ar37 atom decays through electron K capture into a Cl37 atom and a neutrino, plus a gamma ray of wavelength 4.2 Angstroms. The binding energy of the K capture is 3KeV and the mass difference between Ar37 and Cl37 is 816KeV. We've been asked to calculate the recoil energy of the Cl37 atom when the neutrino is emitted. We know the answer is 9.6eV but can't seem to get anywhere near it!

So far I've calculated the Q value to be 813KeV through the mass difference minus the binding energy of the captured electron. I've tried using linear momentum conservation knowing that the energy of the neutrino is E = pc. However, I can't even see how to begin.

Can anyone offer any starters? I've tried searching everywhere :( Thanks. I believe these are all the values we need to calculate it, but i am at a loss on what to do!

[I realize this should be in a specific form but I'm literally about to go out right now, I will be back later and edit it if nessesary, thanks]
 
Have you taken the X-ray into account in your momentum conservation calculations?
 
Just want to say this has been solved now :)
 
Thanks. This has been solved now! Didn't need to take into account the x-ray emission. It was simply a case of using E = p^2/2m...doh!
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
4
Views
3K
Replies
3
Views
3K
  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 38 ·
2
Replies
38
Views
7K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 23 ·
Replies
23
Views
3K