Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Rectangular and Polar Coordinates with variables

  1. Jun 2, 2010 #1
    1. The problem statement, all variables and given/known data

    I'm trying to help a friend with these two questions, but given that I haven't studied this material in over a decade, it's one of the topics I cannot recall at all.

    Convert the following from rectangular to polar coordinates:

    (a) x2 + y2 = x

    (b) y2 = 2x

    2. Relevant equations

    r2 = x2 + y2

    Tan(T) = y/x, where (T) stands in for theta

    3. The attempt at a solution

    For the first one, I found r = x1/2, aka sqrt (x), but am completely stumped on what to do about finding theta. Arctan (sqrt(x - x2) / (x2 + y2))... yeah, I'm pretty sure that whole tangent thing is useless. Using the reverse procedure (polar to rectangular) gives [sqrt(x) cos (T)]2 + [sqrt(x) sin(T)]2 = sqrt(x) cos(T). Then x cos2(T) + x sin2(T) = sqrt(x) cos(T). Factoring out an x, the cos2 + sin2 identity just gives x = sqrt(x) cos(T), which is... I'm pretty sure it's what was already known.

    For the second: No idea how the two relevant equations could even potentially be useful, but I did notice if you take the reverse procedure (going from polar to rectangular), then using x = r cos(T), y = r sin(T), then [r sin(T)]2 = 2 r cos(T). This eventually reduces to r = 2 cos(T) / sin2(T), or r = 2 cot(T)csc(T), or any number of other expressions that leaves me none the wiser about what the polar coordinates are supposed to resemble.

    I suppose if you substitute y = sqrt(2x), that gives r = sqrt(x2 + 2x). Again, no idea how this is supposed to be useful.
    Last edited: Jun 2, 2010
  2. jcsd
  3. Jun 2, 2010 #2


    User Avatar
    Homework Helper

    Just use the coordinate transformations you stated above.


    you don't need to find the actual value of θ
  4. Jun 2, 2010 #3
    I thought that was for converting polar coordinates to rectangular.

    Anyway, does that mean my solution for the second one is complete, and that the answer should just be r = 2 cos(θ)/sin2(θ)?

    For the second one, I tried redoing the manipulation without substituting sqrt(x) for r. Should the following be correct?

    r2 cos2θ + r2 sin2θ = r cos θ

    r2 = r cos θ

    r = cos θ
  5. Jun 2, 2010 #4


    User Avatar
    Homework Helper

    Yes those should be correct.
  6. Jun 2, 2010 #5
    Thank you very much. I'm certain my friend will appreciate this in the morning.

    Funny how problems can be easier than they seem like this. The other day, I solved half of a Putnam question, then later failed to manage a basic geometry proof involving a circle. It's like sidestepping a pile of horse dung and falling down a manhole cover. There should really be an adjective describing people like me.
  7. Jun 2, 2010 #6


    User Avatar
    Homework Helper

    I think they are called over-thinkers :tongue:
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook