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A(y, 0) = A(y-1, 1) For : y > 0

A(y, x) = A(y-1, A(y, x-1)) For : y > 0, x > 0

Find A(2,x) for x >= 0

I worked this out... but I am wondering if I am right.

Let x be 1 and y be 2.

From statement 3 :

A(y, x) = A(y-1, A(y, x-1)) = A(1, A(2, 0))

From statement 2 & 3 :

A(2,0) = A(1, 1)

Therefore :

A(2,x) = A(1, A(1,1))

Am I right?