Reduction of a simple distributed loading problem

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The discussion highlights the inapplicability of the NOTE method from exercise 4.21 to exercise 4-156 due to differences in the location functions, which are x^2 and x^3, respectively. This distinction leads to different integral results for each case. Consequently, the calculations for distributed loading cannot be directly compared or applied interchangeably. The incorrect assumption that the same method can be used for both exercises is clarified. Understanding the specific functions involved is crucial for accurate problem-solving in distributed loading scenarios.
Renan
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Why can't we use the NOTE method (exercise 4.21) on the exercise 4-156 ?

A = ab/3 = (10.500)/3 = 1666,66 N --> this not right
 

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Renan said:
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Why can't we use the NOTE method (exercise 4.21) on the exercise 4-156 ?
Because the location function is different. In one case is goes as ##x^2## and in the other as ##x^3##. If you do the integral in each case, you will get a different answer.
 
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