Refraction of light in three mediums

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arnavchhabra
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1. 2 cases:
there are three mediums
first case: light travels from first medium to second, then to third. n1 = 1.1; n2 =1.6; n3 =1.9
angle of incidence before first = theta 1
angle of refraction after first = theta 2
angle of refraction after second = theta 3

second case:
light travels through three mediums
n1' = n1
n2' = 1.5
n3' = n3
theta 1' = theta 1




2. R = sin theta 3' / sin theta 3
what should be the value of R?




3. I keep getting 1. I donno why though?
 
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Snell's Law for the general case says that n1sin(theta1) = n2sin(theta2) and since the angle into the second interface is the same as the angle out of the first interface, n2sin(theta2) = n3sin(theta3). So n1sin(theta1) = n3sin(theta3). So the index of refraction of the middle medium doesn't change the final angle out. That's the meaning of R=1, right?
 
yes...i don't think its right though