Regarding ' The Electric field inside a non conducting shell '

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Homework Help Overview

The discussion revolves around the electric field inside a uniformly charged non-conducting spherical shell, particularly in the context of a point charge located outside the shell. Participants are exploring the implications of Gauss's law and the superposition principle in this scenario.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Gauss's law and the implications of having no charge enclosed by a Gaussian surface inside the shell. There is an exploration of the reasoning behind the assumption that the electric field must be zero based on the flux being zero.

Discussion Status

Some participants are questioning the validity of moving the electric field out of the integral in the context of Gauss's law. There is a suggestion to reconsider the symmetry of the problem and the effects of the uniformly charged shell on the electric field within it.

Contextual Notes

Participants note the importance of the shape of the shell and clarify that it is a spherical shell, which may influence the discussion on symmetry and electric field behavior.

Uday
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Homework Statement


There is a Uniformly charged Non conducting Spherical shell along with a point charge external to the shell . they make up an isolated system . Find the electric field inside the shell .


Homework Equations





The Attempt at a Solution

Actually using superposition principle we obtain that the field is actually non zero . But in order to calculate the electric field inside the shell if i use gauss law by considering a gaussian surface inside the shell ... there will be no charge enclosed in it so by gauss law the flux is zero . since in that case ∫E.da = E∫da which is equal to zero . Since ∫da is non zero E must be zero ...
I guess there is some fault with this but I am unable to find it out . So please can u help me .
And thanks for sparing ur valuable time to read this .
 
Last edited:
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Uday said:
∫E.da = E∫da
That will not be true in general. Is anything known about the shape of the shell?
 
haruspex said:
That will not be true in general. Is anything known about the shape of the shell?

Im sorry that's a spherical shell
and i have edited my question .
 
Last edited:
Hello Uday

Uday said:
Actually using superposition principle we obtain that the field is actually non zero . But in order to calculate the electric field inside the shell if i use gauss law by considering a gaussian surface inside the shell ... there will be no charge enclosed in it so by gauss law the flux is zero . since in that case ∫E.da = E∫da which is equal to zero . Since ∫da is non zero E must be zero ...
I guess there is some fault with this but I am unable to find it out . So please can u help me .
And thanks for sparing ur valuable time to read this .

I think the problem lies in concluding that if the flux across the gaussian spherical surface is zero ,then the electric field is zero .

What is your reasoning behind moving E out of the integral ∫E.ds ?
 
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Ya ... that's ryt E isn't constant ...
 
Uday said:
Im sorry that's a spherical shell
and i have edited my question .
OK, so forget the point charge for the moment. What field does a uniformly charged spherical shell generate inside itself?
Hint: when considering a Gaussian shell placed concentrically inside it, think about the symmetry.
 

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