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Aerospace Engineering
Regression rate of fuel in rocket nozzle
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[QUOTE="bigfooted, post: 5903107, member: 377103"] When ##\frac{1}{y}\frac{dy}{dt}=-C## then integrating both sides leads to ## \ln(y) = -Ct ## (neglecting the constant of integration) Taking the exponential of the left side leads to ## \exp(\ln(y)) = e^{\ln(y)} = y ## Taking the exponential of both sides leads to ##y = \exp(-Ct) =\frac{1}{e^{Ct}}## hope this helps. [/QUOTE]
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Aerospace Engineering
Regression rate of fuel in rocket nozzle
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