Relating force constant and frequency to mass

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SUMMARY

The discussion focuses on calculating the mass of an object attached to an ideal spring with a force constant of 123 N/m and a frequency of 5.65 Hz. The relationship between the mass, force constant, and the period of oscillation is established using the formula T = 2π√(m/k). The calculated mass is 0.0976 kg, derived from the rearranged formula m = k * (T/(2π))^2. The conversation also touches on the derivation of the period from the force equation F = ma = -kx, emphasizing the importance of understanding these fundamental relationships in simple harmonic motion.

PREREQUISITES
  • Understanding of simple harmonic motion
  • Familiarity with Hooke's Law (F = -kx)
  • Knowledge of the period of oscillation formula (T = 2π√(m/k))
  • Basic calculus concepts for derivation
NEXT STEPS
  • Study the derivation of the period formula for simple harmonic motion
  • Explore the relationship between frequency and period in oscillatory systems
  • Learn about energy conservation in simple harmonic motion
  • Investigate the effects of damping on oscillations
USEFUL FOR

Students in physics courses, particularly those studying mechanics and oscillations, as well as educators looking for examples of practical applications of simple harmonic motion principles.

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Homework Statement



A body of unknown mass is attached to an ideal spring with force constant 123 N/m. It is found to vibrate with a frequency of 5.65 Hz.

Find the mass of the object.

Homework Equations



F=-kx
F=ma
No idea what else...

The Attempt at a Solution



No idea where to start. I get to:

ma=-kx
m = (-123x) / (a)

and can't think where to go from there. I've tried:

1cycle=4 max displacments (x), so
f=5.65Hz = 22.6 cycles of x /s

thereby returning x as .25, but that's dead wrong. Any ideas? I'm totally lost.
 
Last edited:
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The mass executes simple harmonic motion. In the relevant theory you can find a relation between the period of oscillations, the mass of the object and the force contant.
 
Alright, I got it.

T = 2(pi)*sqrt(m/k)

m = k * (T/(2(pi)))^2 = 9.76E-2

Just for curiosity's sake, was there any other way to do it, that wasn't much harder?
 
That's the only way I know of.
 
Vidatu said:
Alright, I got it.

T = 2(pi)*sqrt(m/k)

m = k * (T/(2(pi)))^2 = 9.76E-2

Just for curiosity's sake, was there any other way to do it, that wasn't much harder?

If you're in a calculus-based course, you might be expected to know *how* to get from the force equation F = ma = -kx to the result for the period. But, in the end, you would still apply the period formula you used here.
 

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