Relation between bandwidth and ssamplig rate

[amaresh92]

greetings,
how a sampling rate can define bandwidth required for transmission of that signal.if sampling rate is high then bandwidth requirement is also high,how?

 

[Runei]

In order not to have spectral aliasing of the discrete signal, you need to have a sampling rate that is 2 times the bandwidth. So the relationship is simple

F = 2B

 

[Runei]

In order not to have spectral aliasing of the discrete signal, you need to have a sampling rate that is 2 times the bandwidth. So the relationship is simple

F = 2B

 

[sophiecentaur]

In order not to have spectral aliasing of the discrete signal, you need to have a sampling rate that is 2 times the bandwidth. So the relationship is simple

F = 2B

There is a small problem with using that basic definition for practical sampled systems. Bandwidth is not usually defined in terms of the difference between the maximum and minimum frequencies involved. The value of B, in the quote would be defined as above but system bandwidth is usually defined in different terms.
Because all communications systems (transmitters and receivers) have 'real' channel-defining filters, which will never have a completely 'sharp cut' characteristic, the bandwidth is usually defined in terms of 'half power bandwidth' - that is the interval between points on the filter where the admitted power is half. There are always 'skirts' which allow a finite level of components to fall outside this bandwidth value. Hence, if you want to avoid aliasing, your sampling frequency needs to be somewhat in excess of twice the bandwidth. The more fussy you have to be about the phase response of the analogue channel, the wider the skirts of anti aliasing filters need to be - so the more excess sampling rate you need.

 

[alphysicist]

Greetings,

I can provide some insight into the relationship between bandwidth and sampling rate. Bandwidth refers to the range of frequencies that a signal can occupy, while sampling rate refers to the rate at which a signal is sampled or measured.

In order to accurately represent a signal, the sampling rate must be at least twice the highest frequency present in the signal, according to the Nyquist-Shannon sampling theorem. This means that a higher sampling rate is necessary to accurately capture a signal with a wider bandwidth.

For example, if a signal has a bandwidth of 1 kHz, a sampling rate of at least 2 kHz is needed to accurately capture it. However, if the same signal has a bandwidth of 10 kHz, a sampling rate of at least 20 kHz is needed.

Therefore, as the bandwidth of a signal increases, the sampling rate required to accurately represent it also increases. This is because a higher sampling rate captures more data points, allowing for a more accurate representation of the signal's frequency content.

In conclusion, the relationship between bandwidth and sampling rate is that a higher sampling rate is necessary to accurately capture and transmit a signal with a wider bandwidth. I hope this helps to clarify the concept.

Best regards,