Relations between torque for system of pulleys

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SUMMARY

The discussion focuses on deriving the transfer function for a pulley system by establishing equations based on the moments of inertia and tensions acting on the pulleys. Key equations include Iθ'' = Σ M and M = r x F. The user attempts to equate moments from different pulleys but faces confusion regarding the conditions under which this is valid, particularly when masses are involved. A critical insight is the need to account for all torques acting on each pulley and to establish a consistent convention for positive and negative directions of rotation.

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  • Understanding of rotational dynamics and moment of inertia
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BeeKay
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Homework Statement


In an attempt to find a transfer function of the system, I need to come up with equations that I can use to solve for unknowns. See the attached image to see the diagram of the pulley system. J is the moment of inertia, r is the radius. The smaller radius on pulley 2 is r1. Let me know if you can't access the picture.

I believe the sum of the moments on the first pulley should equal that on the second and third, but I do not know

Homework Equations


Iθ'' = Σ M
M = r x F

The Attempt at a Solution


1) J1 θ1'' = τ + r1(T1-T2)
2) J2θ2'' = r2(T3-T4)
3) J3θ3'' = r2(T3-T5)
4) x = r2θ2
5) x = r2θ3
6) mx'' = T4-T5 -kx

I feel that I can set equations 1 and 2 equal to each other because there is not a mass or anything between them. I do not think that I can set 2 and 3 equal to each other because it is connected to a mass. But I honestly do not know the actual reasons behind why I can and/or cannot equate them. Equations 4 and 5 tell me that θ1 is equal to θ2, but because they have different moments of inertia the sum of the moments cannot be the same.

Any help is appreciated regarding which equations I can set equal to each other and more importantly what allows me to do that. Thanks
 

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BeeKay said:

Homework Statement


In an attempt to find a transfer function of the system, I need to come up with equations that I can use to solve for unknowns. See the attached image to see the diagram of the pulley system. J is the moment of inertia, r is the radius. The smaller radius on pulley 2 is r1. Let me know if you can't access the picture.

I believe the sum of the moments on the first pulley should equal that on the second and third, but I do not know

Homework Equations


Iθ'' = Σ M
M = r x F

The Attempt at a Solution


1) J1 θ1'' = τ + r1(T1-T2)
2) J2θ2'' = r2(T3-T4)
3) J3θ3'' = r2(T3-T5)
4) x = r2θ2
5) x = r2θ3
6) mx'' = T4-T5 -kx

I feel that I can set equations 1 and 2 equal to each other because there is not a mass or anything between them. I do not think that I can set 2 and 3 equal to each other because it is connected to a mass. But I honestly do not know the actual reasons behind why I can and/or cannot equate them. Equations 4 and 5 tell me that θ1 is equal to θ2, but because they have different moments of inertia the sum of the moments cannot be the same.

Any help is appreciated regarding which equations I can set equal to each other and more importantly what allows me to do that. Thanks
In equation 2 I think you are missing the torques attributed to the tensions T_1 and T_2. Keep in mind that this pulley has a total of four torques acting on it, one from each of the four belt/line segments: two from the bottom and two from the left.

Other than that, be mindful of your own convention (you get to decide) of what direction is positive and what is negative. In other words, is clockwise positive or is counterclockwise positive? This will make a difference in whether you express a term as, say, r_2 \left( T_3 - T_5 \right) or instead as r_2 \left( T_5 - T_3 \right) for example.
 

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