- #1
wumple
- 60
- 0
Is there some sort of relationship between the differential
[tex]dx[/tex]
and the differential operator which means to take the derivative [tex]d/dx[/tex]
if x is a dependent variable? My prof said that [tex] dx * d/dx = 1[/tex] but that doesn't seem to work out in the case I'm looking at, so I must be missing something.
[tex]dx[/tex]
and the differential operator which means to take the derivative [tex]d/dx[/tex]
if x is a dependent variable? My prof said that [tex] dx * d/dx = 1[/tex] but that doesn't seem to work out in the case I'm looking at, so I must be missing something.