Relationship between potential and induced emf?

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SUMMARY

The discussion centers on the relationship between potential and induced electromotive force (emf) in a semicircular wire moving through a magnetic field. The induced emf is calculated using the formula E = BLv, where B is the magnetic field strength, L is the effective length of the wire, and v is the velocity of the wire. It is established that point N is at a higher potential than point M due to the direction of the induced current, which flows from M to N. The conversation also clarifies that the equation can be applied even if the circuit is not closed, emphasizing the importance of understanding the effective length used in calculations.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Familiarity with Fleming's Left-Hand Rule
  • Knowledge of magnetic fields and their interaction with conductors
  • Concept of potential difference in electrical circuits
NEXT STEPS
  • Study the application of Faraday's Law in open and closed circuits
  • Learn about the effects of resistance on induced emf in circuits
  • Investigate the significance of effective length in electromagnetic induction calculations
  • Explore advanced topics in electromagnetic theory, such as Lenz's Law
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Physics students, electrical engineers, and educators seeking to deepen their understanding of electromagnetic induction and its applications in real-world scenarios.

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Homework Statement



[PLAIN]http://img220.imageshack.us/img220/2589/44045733.png

Semicircular wire MN of diameter L moves with speed v perpendicularly through a uniform magnetic field of strength B.

1. Find the magnitude of the induced emf generated between M and N.
2. State whether M or N is at a higher potential.

Homework Equations



E = BLv

The Attempt at a Solution



1. Given answer: Induced emf = BLv

However, I was wondering if you can use that equation even if it's not a closed circuit?
In the semicircular wire, there shouldn't be magnetic flux linkage. And even if there was, there is no change in magnetic flux linkage.

2. N is at a higher potential

There is opposing force that resists the motion of the wire (:confused: is this reason correct?), which, by Fleming's left hand rule, results in an induced current (if the circuit were to be closed) flowing from M to N. Thus, N is at higher potential as a result of the induced "current".

However, I know that current flows from higher potential to lower potential. So is it right to say that in the case of an induced current, if it flows from M to N, N is at a higher potential?
 
Last edited by a moderator:
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However, I was wondering if you can use that equation even if it's not a closed circuit?

Sure, you can, you have to.
Just be careful what "length" is.

If it was a closed circuit of zero resistance, there would be no voltage at all.
V=RI, R=0, so V=0 (for closed loops of zero resistance)

However, I know that current flows from higher potential to lower potential. So is it right to say that in the case of an induced current, if it flows from M to N, N is at a higher potential?

Pay attention to the charge sign.

There is opposing force that resists the motion of the wire

No there's no opposing force.
 
No there's no opposing force.

Then how is there an induced emf?

[PLAIN]http://img207.imageshack.us/img207/5853/93128344.png

Do you take "Force" to be in direction of the velocity?
 
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i know the thread is old but i have a question
what shall we take as a length to calculate E, the length πr of the arc or the length 2r of the line segment and why?
thanks a lot
 

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